[tex]{ \huge{ \textup{ \purple{jawaban}}}}[/tex]
[tex] \sf 1. )\: - 4 - 75 \div ( - 3) + 14[/tex]
[tex] \sf = - 4 - ( - 25) + 14[/tex]
[tex] \sf = 21 + 14[/tex]
[tex]{\huge{ \green{ \boxed{ \blue{ \bold{ = 35}}}}}} [/tex]
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[tex] \sf 2.)- 50 \times 18 \div 6[/tex]
[tex] \sf = - 900 \div 6[/tex]
[tex]{\huge{ \green{ \boxed{ \blue{ \bold{ = - 150}}}}}} [/tex]
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[tex] \sf3.) \: L = \frac{1}{4} \times \pi \times {r}^{2} [/tex]
[tex] \sf L = \frac{1}{4} \times \frac{22}{7} \times {14}^{2} [/tex]
[tex] \sf L = \frac{1}{4} \times \frac{22}{ \cancel{ \: 7 \: }} \times { \cancel{196}}[/tex]
[tex] \sf L = \frac{1}{ \cancel{ \: 4 \: }} \times 22 \times { \cancel{28}}[/tex]
[tex] \sf L = 1 \times 22 \times 7[/tex]
[tex]{\huge{ \green{ \boxed{ \blue{ \bold{ L= 154 \: {cm}^{2} }}}}}} [/tex]
Maka, luas lingkaran 154 cm².
-
[tex] \sf4.) \: K = 2 \times \pi \times r[/tex]
[tex] \sf K = 2 \times 3.14 \times 50[/tex]
[tex] \sf K = 6.28 \times 50[/tex]
[tex]{\huge{ \green{ \boxed{ \blue{ \bold{K = 314 \: cm}}}}}} [/tex]
Maka, keliling 314 cm.
-
[tex] \sf5.) \: V = {s}^{3} [/tex]
[tex] \sf V= 25 {}^{3} [/tex]
[tex] \sf V = 25 \times 25 \times 25[/tex]
[tex]{\huge{ \green{ \boxed{ \blue{ \bold{ V= 15625\: cm {}^{3} }}}}}}[/tex]
Maka, volume kubus 15625 cm³.
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Penjelasan dengan langkah-langkah:
1. (-4) - 75:(-3) + 14
(-4) + 25 + 14
21 + 14 = 35
2. (-50) ×18 : 6
-900 : 6 = - 150
3. 1/4 luas lingkarang dengan diameter 28 cm:
Jari - jari = 14
[tex] \frac{\pi {r}^{2} }{4} = \frac{ \frac{22}{7} \times {14}^{2} }{4} [/tex]
[tex] \frac{ \frac{22}{7 } \times 196}{4} = \frac{22 \times 28}{4} [/tex]
[tex] \frac{616}{4} = 152[/tex]
Jadi luas 1/4 lingkaran adalah 152 cm
4. Keliling lingkaran dengan jari- jari 50 cm:
[tex]k = 2\pi \: r[/tex]
[tex]k = 2 \times \frac{22}{7} \times 50[/tex]
[tex]k = \frac{2200}{7} = 314[/tex]
jadi keliling lingkarang adaah 314 cm
5. Volume kubus dengan panjang sisi 25cm:
[tex]v = {s}^{3} [/tex]
[tex]v = {25}^{3} [/tex]
[tex]v = 25 \times 25 \times 25 = 15625 {cm}^{3} [/tex]
Semoga Membantuu:)
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